Radioactive Emissions

A radon nucleus ${}^{222}\mathrm{Rn}_{86}$ undergoes $\mathrm{\alpha }$-decay, the resulting nucleus is

In gamma ray emission from a nucleus,

The particles emitted during the sequential radioactive decay of ${}^{238}\mathrm{U}_{92}$ to ${}^{206}\mathrm{Pb}_{82}$ are

A nucleus $\mathrm{X}$ captures a $\beta$ particle and then emits a neutron and $\mathrm{\gamma }$ ray to form $\mathrm{Y}. \mathrm{X}$ and $\mathrm{Y}$ are:-

Write balanced nuclear equations for each of the following:
($a$) $\mathrm{\alpha }$ -emission from curium-$242$
($b$) $\mathrm{\beta }$ -emission from magnesium-$28$
($c$) positron emission from xenon-$118$

Calculate the number of $\mathrm{\alpha }$ and $\mathrm{\beta }$-particles emitted in the change:
${}_{92}{}^{235}\mathrm{U}⟶{}_{82}{}^{207}\mathrm{Pb}$

The heavier element continuously emits $\mathrm{\alpha }$ and $\mathrm{\beta }$ particles. To which group the finally stable element may belong ?

What is the total number of $\mathrm{\alpha }$ and $\mathrm{\beta }$ particles emitted in the nuclear reaction, ${\mathrm{ }}_{92}^{238}\mathrm{U}\to {\mathrm{ }}_{82}^{214}\mathrm{Pb}$ ?

From the nuclear reaction${\mathrm{ }}_{92}^{238}\mathrm{U}\to {\mathrm{ }}_{82}^{214}\mathrm{Pb}$ find the total number of $\mathrm{\alpha }- \mathrm{and} \mathrm{\beta }$ particles emitted.

${}_{13}^{27}\mathrm{Al}$ is a stable isotope. ${}_{13}^{29}\mathrm{Al}$ is expected to be disintegrated by

A new radionucleide is obtained from the radionucleide ${ }_{\text{90}}^{\text{234}}\mathrm{T}\mathrm{h}$ through two successive $\mathrm{\beta }$ -decays followed by one $\mathrm{\alpha }$ -decay. The atomic number and the mass number respectively of the resulting radionucleide is

Which of the given radiations is having high penetrating power and not affected by electrical and magnetic field?

$\mathrm{ }{ }_{88}^{228}X\stackrel{-3\alpha }{\to }B\stackrel{-\beta }{\to }Y.$ The element $Y$ is

An element E loses one $\alpha$ and two $\beta$ particles in three successive stages. The resulting element will be

Calculate the number of $\alpha$ and $\beta$ particles in the following change.

${\mathrm{ }}_{92}^{235}\mathrm{U}\to {\mathrm{ }}_{82}^{207}\mathrm{ }\mathrm{Pb}$

Find the neutron - proton ratio in the daughter element when one $\alpha$ - particle is emitted by ${}_{92}{}^{238}U.$

The atomic mass and atomic number of lead are 208 and 82. The atomic mass and atomic number of bismuth are 209 and 83. The neutron/proton ratio in these atoms is

${}_{92}\mathrm{U}^{235}$ nucleus absorbs a neutron and disintegrates into ${}_{54}\mathrm{Xe}^{139} , {}_{38}\mathrm{Sr}^{94} \mathrm{and} \mathrm{x}$. What will be the product x ?

An isotope of Th²³¹ can be converted into Th²²⁷ by the emission of

${}_{\text{11}}^{\text{23}}\text{Na}$ emits a positron and form nuclide. The ratio of the atomic mass and atomic number of the resulting nuclide is